626 Views

Two equal spheres are identically charged with q of electricity separately. when they are placed at a distance 3R from centre to centre where R is the radius of either sphere the force of repulsion between them is


Vikram Kumar 21st Aug, 2021
Answer (1)
Ayush 21st Aug, 2021

Hello candidate,

Since there are two identically charged in nature, and because of the law of same charges repel each other there will be a repulsive force initiated between the two spherical bodies. Moreover, the electrostatic forces of repulsion attraction between any two charged body is given by the formula (k* q1*q2/ r^2), and here the value of r is equal to 3R and q1 is equal to q2 is equal to q. Hence, the force expression can be termed as- k*q^2/r^2.

Hope you found it informational. If you have any further queries feel free to post it out!!

Related Questions

UPES B.Tech Admissions 2026
Apply
Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
UPES Integrated LLB Admission...
Apply
Ranked #18 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS Rankings | 16 LPA Highest CTC
Presidency University MBA Adm...
Apply
NAAC A+ Accredited | Highest CTC 10 LPA | Top Recruiters : Amazon, Accenture, KPMG, EY, Capgemini & many more
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC | Ranked 33rd by NIRF 2025
UPES M.Tech Admissions 2026
Apply
Ranked #45 Among Universities in India by NIRF | 1950+ Students Placed 91% Placement, 800+ Recruiters
UPES | BBA Admissions 2026
Apply
#36 in NIRF, NAAC ‘A’ Grade | 100% Placement, up to 30% meritorious scholarships
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books