Question : Two numbers are in the ratio 9 : 16. If both numbers are increased by 40, then their ratio becomes 2 : 3. What is the difference between the two numbers?
Option 1: 64
Option 2: 60
Option 3: 48
Option 4: 56
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 56
Solution : Let the two numbers as $9x$ and $16x$. According to the problem, if both numbers are increased by 40, their ratio becomes 2 : 3. $⇒\frac{9x + 40}{16x + 40} = \frac{2}{3}$ $⇒27x + 120 = 32x + 80$ $⇒5x = 40$ $⇒x = 8$ So, the two numbers are: $⇒9x = 9 \times 8 = 72$ $⇒16x = 16 \times8 = 128$ The difference between the two numbers = 128 – 72 = 56 Hence, the correct answer is 56.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : If the ratio of the diameters of two right circular cones of equal height is 3 : 4, then the ratio of their volume will be:
Question : The sum of the two numbers is 37 and the difference between their squares is 185, then the difference between the two numbers is:
Question : If the ratio of the altitudes of two triangles is 3 : 4 and the ratio of their corresponding areas is 4 : 3, then the ratio of their corresponding lengths of bases is:
Question : If the difference between the two numbers is 20 percent of their sum, then what is the ratio of larger number and smaller number?
Question : The ratio of three numbers is 6 : 5 : 9. If 20% of the first number is 30, then what would be 50% of the difference between the third and second numbers?
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile