Question : Two numbers, when divided by a certain divisor, leave the remainder 57. When the sum of the two numbers is divided by the same divisor, the remainder is 49. The divisor is:
Option 1: 56
Option 2: 57
Option 3: 49
Option 4: 65
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 65
Solution :
Let the two numbers be $a$ and $b$ and the divisor is $d$.
According to the question,
$a = d×p + 57$ and $b=d×q + 57$, where $p$ and $q$ are the quotients.
Adding these two equations we get,
$(a+b)=d(p+q)+114$
Again when the sum of the two numbers is divided by the same divisor, the remainder is 49.
$\therefore$ Divisor = (114 – 49) = 65
Hence, the correct answer is 65.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
