Question : Two people, A and B, are at a distance of 260 km from each other at 9:00 a.m. A immediately starts moving towards B at a speed of 25 km/hr and at 11:00 a.m., B starts moving towards A at a speed of 10 km/hr. At what time (in p.m.) will they meet each other?
Option 1: 5:00
Option 2: 6:00
Option 3: 6:30
Option 4: 7:00
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Correct Answer: 5:00
Solution : Given: A's speed = 25 km/hr B' speed = 10 km/hr Distance traveled by A from 9 a.m. to 11 a.m. or in 2 hours = 25 × 2 = 50 km Remaining distance = (260 – 50) = 210 km When two persons move toward each other, their relative speed is the sum of their speeds. So, relative speed = 25 + 10 = 35 km/hr Time taken by them to cover the remaining 210 km = $\frac{210}{35}$ = 6 hours So, they will meet at 6 hours from 11 a.m. i.e. at 5 p.m. Hence, the correct answer is 5:00.
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Question : Two cities A and B are 135 km apart on a straight track. One car starts from A at 8 a.m. and travels towards B at 25 km/hr. Another car starts from B at 9 a.m. and travels towards A at a speed of 30 km/hr. At what time will they meet?
Question : A thief steals a van at 3:00 a.m. and drives it at a speed of 57 km/h. The thief is discovered at 4:00 a.m. and the owner starts chasing in another van, at a speed of 76 km/h. At what time will he catch the thief?
Question : $S_1$ and $S_2$ are two stations that are 195 km apart. A train starts from $S_1$ at 4:00 pm and moves towards $S_2$ at the speed of 65 km/hr. Another train starts from $S_2$ at 5:00 pm and moves towards $S_1$ at the speed of 35 km/hr. At what time will the two trains meet?
Question : Vikas covered a certain distance by bike. If he covers 40% of the distance at 40 km/hr, 50% of the distance at 25 km/hr and the remaining 10% distance at 10 km/hr. Find his average speed over the whole distance.
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