Question : Two people, A and B, are at a distance of 260 km from each other at 9:00 a.m. A immediately starts moving towards B at a speed of 25 km/hr and at 11:00 a.m., B starts moving towards A at a speed of 10 km/hr. At what time (in p.m.) will they meet each other?
Option 1: 5:00
Option 2: 6:00
Option 3: 6:30
Option 4: 7:00
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Correct Answer: 5:00
Solution : Given: A's speed = 25 km/hr B' speed = 10 km/hr Distance traveled by A from 9 a.m. to 11 a.m. or in 2 hours = 25 × 2 = 50 km Remaining distance = (260 – 50) = 210 km When two persons move toward each other, their relative speed is the sum of their speeds. So, relative speed = 25 + 10 = 35 km/hr Time taken by them to cover the remaining 210 km = $\frac{210}{35}$ = 6 hours So, they will meet at 6 hours from 11 a.m. i.e. at 5 p.m. Hence, the correct answer is 5:00.
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