Question : Two stations L and M are 720 km apart from each other. A train leaves from L to M, and another trains leave from M to L simultaneously. Both trains meet after 24 hours. If the speed of the first train is 10 km/hr more than the second train, then what is the speed of the slower train?
Option 1: 20 km/hr
Option 2: 16 km/hr
Option 3: 14 km/hr
Option 4: 10 km/hr
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Correct Answer: 10 km/hr
Solution : Distance between L and M = 720 km Time taken in meeting = 24 hours Difference of speed of 1st train and 2nd train = 10 km/hr Let the speed of the faster train be $x$ and the slower train be $x-10$. Here the speed is the relative speed in the opposite direction We know that, Relative speed = $\frac{\text{Distance}}{\text{Time}}$ ⇒ $x + x - 1 0 = \frac{720}{24}$ ⇒ $2x =30 + 10$ ⇒ $x=20$ The speed of the slower train is = 20 – 10 = 10 km/hr Hence, the correct answer is 10 km/hr.
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