Question : There are 3 taps, A, B, and C, in a tank. These can fill the tank in 10 h, 20 h, and 25 h, respectively. At first, all three taps are opened simultaneously. After 2 h, tap C is closed, and taps A and B keep running. After 4 h, tap B is also closed. The remaining tank is filled

Question : Directions: A tap can fill up a tank of 1250 litres in 4 hours, whereas another tap can fill the same tank in 8 hours. An outlet tap can empty that tank in 6 hours. If all three taps are opened simultaneously, then how much time will it take to fill the

Question : Taps A and B can fill a tank in 15 minutes and 10 minutes, respectively while tap C can empty the full tank in x minutes. If all three taps are opened together, the tank is filled completely in 8 minutes. Tap C alone will empty $\frac{3}{8}$ th part of the tank in:

Question : Pipes A, B and C can fill a tank in 10, 15 and 30 hours, respectively. D is an emptying pipe which alone can empty the full tank in $x$ hours. A, B and C are opened together for 3 hours and then closed. Now D is opened which alone empties the tank in 30 hours. What is the

Question : Two pipes A and B can fill a tank in 6 hours and 8 hours respectively. If both the pipes are opened together, after how many hours should B be closed so that the tank is full in 4 hours?