Question : Two trains are moving in the same direction at 36 km/hr and 48 km/hr. The time taken by the faster train to cross a man sitting in the slower train is 33 seconds. What will be the length of the faster train?
Option 1: 770 metres
Option 2: 90 metres
Option 3: 110 metres
Option 4: 180 metres
Correct Answer: 110 metres
Solution :
Relative speed = 48 – 36 = 12 km/hr = 12 × $\frac{5}{18}$ = $\frac{10}{3}$ m/s
Time taken = 33 seconds
Distance = $\frac{10}{3}$ × 33 = 110 metres
Length of the faster train = 110 metres
Hence, the correct answer is 110 metres.
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