Question : Two years ago, the population of a small town was 60,000. It increased by 5% in the first year, but due to the pandemic, it decreased by 10% in the second year. What is its present population (after the end of 2 years)?
Option 1: 56,700
Option 2: 56,900
Option 3: 3300
Option 4: 55,700
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 56,700
Solution : Population 2 years ago = 60,000 Population after increment of 5% = $60000 × \frac{105}{100}$ = $63000$ Population after decrement of 10% = $63000 × \frac{90}{100}$ = $56700$ Hence, the correct answer is 56,700.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : The population of the village was 12,000 two years ago. If it increased by 2.5% and 3%, respectively, in the last two years, then what is the present population of the village?
Question : The population of the city was 12,50,000 in the year 2010. It increased at the rate of 2% per annum during the years 2011 and 2012. In the year 2013, it decreased by 1%. Find the population of the city at the end of 2013.
Question : The population of a city increases compounded by 10% annually. The present population of this city is 1,33,100. What was the population of the city 2 years ago?
Question : The population of a town increased from 100000 to 250000 in 5 years. What is the approximate compounded percent increase in population per year?
Question : The population of a certain village increases by 5% annually. Its present population is 8200. After two years the population will be (approximately):
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile