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using Gauss law obtain in the expression for electric field intensity at a point outside a charged hollow sphere


Puja 1st May, 2020
Answer (1)
Tushar Karmakar 10th May, 2020

Let, R be the radius of the shell and Q be the charge uniformly distributed on the surface.

i) For a point outside the shell :

E×4pi r^2 = Qen/epsilon

From this equation you can easily find the equation of electric field outside the hollow sphere. But inside the hollow sphere there is no enclosed charge present so E=0 inside the sphere.


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