182 Views

using Gauss law obtain in the expression for electric field intensity at a point outside a charged hollow sphere


Puja 1st May, 2020
Answer (1)
Tushar Karmakar 10th May, 2020

Let, R be the radius of the shell and Q be the charge uniformly distributed on the surface.

i) For a point outside the shell :

E×4pi r^2 = Qen/epsilon

From this equation you can easily find the equation of electric field outside the hollow sphere. But inside the hollow sphere there is no enclosed charge present so E=0 inside the sphere.


Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
Jindal Global Law School Admi...
Apply
Ranked #1 Law School in India & South Asia by QS- World University Rankings | Merit cum means scholarships | Regular Admissions Deadline: 30th Apr'25
UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS University Rankings | 16.6 LPA Highest CTC
IILM University Law Admission...
Apply
BA LLB (Hons.) | BBA LLB (Hons.) | LLM | 30 years of Excellence | Merit Scholarships and need based Financial support
Manav Rachna University Law A...
Apply
Admissions open for B.A. LL.B. (Hons.), B.B.A. LL.B. (Hons.) and LL.B Program (3 Years)
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books