Question : $A$ varies directly as $(B+18)$ and $A=108$ when $B=36$. Find the value of $A$ when $B=68$.
Option 1: 75
Option 2: 86
Option 3: 127
Option 4: 172
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 172
Solution : A varies directly as $(B+18)$ So, $\frac{A_1}{A_2} = \frac{B_1+18}{B_2+18}$ ⇒ $\frac{108}{A_2} = \frac{36+18}{68+18}$ ⇒ $\frac{108}{A_2} = \frac{54}{86}$ ⇒ $A_2 = 172$ Hence, the correct answer is 172.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : X is directly proportional to the square of Y. When X is 12, then Y is 2. Find the value of X when Y is 3.
Question : A varies directly as the positive square root of B, and inversely as the cube of C. If A = 15, when B = 27 and C = 2, then find B when A = 9 and C = 2.
Question : The height of an equilateral triangle is 18 cm. Its area is:
Question : If $(a+b+c)=14$ and $\left(a^3+b^3+c^3-3abc\right)=98$, find the value of $\left(a^2+b^2+c^2\right)$.
Question : If $(a+b+c)=19$ and $\left(a^2+b^2+c^2\right)=155$, find the value of $(a-b)^2+(b-c)^2+(c-a)^2$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile