Water is flowing at a rate of 2m/s in a pipe of radius 8cm. If the radius is reduced to half, the rate of flow is
Hi aspirant
Using the equation of continuity, we can solve this problem
A1*V1=A2*V2
A= Area of the pipe; Π r2
V= Velocity of water
x= rate of flow in a reduced radius
Applying the equation,
π r 12 * V1= π r22 *V2
So, 64*2 = 16*X
64*2/16=X
X= 8m/s.