Hello, Aadarsh Hanuman

Result of Paper 2 of JEE main 2019 will carry total normalized NTA scores obtained by the candidate in the first and second attempt along with All India Rank (AIR) and All India Category Rank. The raw marks obtained by candidates who have appeared in JEE Main 2019 will be normalized for the compilation of scores, so that it will help to equalize the difficulty levels of both attempts.

JEE Main Cutoff for B.Arch

COLLEGE                                         CATEGORY      OPENING RANK          CLOSING RANK

Malaviya National Institute of              GENRAL          568                            2401

Technology Jaipur                              SC                 99                              589

ST                 160                            498

OBC               392                            1688

Maulana Azad National                       GENRAL            232                             3235

Institute of Technology Bhopal           OBC                  583                             2192

ST                    29                               439

SC                    190                             765

National Institute of Technology         GENRAL              663                             1141

Calicut                                           OBC                    244                              393

ST                      229                               229

SC                      127                              577

National Institute of Technology         GENRAL              2491                             1120

Hamirpur                                         OBC                   2184                             38348

SC                     445                               1269

ST                      320                               486

You can find some more in below provided link

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

ALL THE BEST

THANK YOU

Hello Aadarsh

Percentile system has been introduced by NTA from this year ,In previous year the admission in IIT's is based on ranks from the marks scored by student.So we dont know what will be the cutt off 2019 for different NIT's and IIT's . To know this we have to wait till april when both the atttempts will be over .

You can check previous year cutt off by visiting our website.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

I hope you get  my point.

Good Luck!!!

Hello Aadarsh Hanuman,

As far as I know, IISc, all IITs and NITs have a cutoff of 60 percent. You may have to try state universities. However, the admissions page of IIIT Hyderabad doesn't seem to talk about the minimum BTech percentage, so I guess their test and the interview are the only criteria for selection. You can check the admissions page of IIIT-Hyderabad for details.

Your percentage is 58 % so don’t worry, you will get IISC and IITB for that you need to score 90+ percentile , in top 100 Rank ! If you don’t get call from these two colleges no need to worry, you have to work hard bit during admission process, like you have to send them email regarding your score and percentage, depending on your score they will call you

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