(x + y)²= x² + 2xy + y²
(x – y)² = x² – 2xy + y²
x² – y²= (x + y) (x – y)
(x + y)³ = x³ + y³+ 3xy (x + y)
(x – y)³ = x³ – y³ – 3xy(x – y) = x³ – 3x²y + 3xy² – y³
Question : Compute the expression (299)² using algebraic identities.
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