Hello,

In 2020 the cut off rank to get admission to Computer Science Engineering in round 3 was 8663 to get admission in to Manipal University, Jaipur. Considering the previous year cut off you need to secure a rank below 8600 because the cut off may increase or decrease depending on the total number of candidates appeared, difficulty level of examination and total number of seats available etc. It is quite difficult to predict the minimum marks because the rank vs marks trend changes depending on the highest score in the exam, total marks, normalized score, total number of candidates appeared etc. Last year MET was conducted for 800 marks and this year it is conducted for 240 marks so the rank vs marks trend will change. A safe score to secure a rank below 8600 is 175-195 marks or above. This is an estimated score, the actual rank may vary with this estimated score based on the factors discussed above.