Question : What is $\sin \alpha - \sin\beta$?
Option 1: $2 \cos \frac{\alpha+\beta}{2} \sin \frac{\alpha-\beta}{2}$
Option 2: $2 \sin \frac{\alpha+\beta}{2} \sin \frac{\alpha-\beta}{2}$
Option 3: $2 \cos \frac{\alpha-\beta}{2} \sin \frac{\alpha+\beta}{2}$
Option 4: $2 \cos \frac{\alpha+\beta}{2} \cos \frac{\alpha-\beta}{2}$
Correct Answer: $2 \cos \frac{\alpha+\beta}{2} \sin \frac{\alpha-\beta}{2}$
Solution :
The formula of $\sin α - \sin β$ is given by $2 \cos \frac{\alpha+\beta}{2} \sin \frac{\alpha-\beta}{2}$.
Hence, the correct answer is $2 \cos \frac{\alpha+\beta}{2} \sin \frac{\alpha-\beta}{2}$.
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