What is minimum marks or rank is required to get IIT DELHI in CSE in OBC category .
Answer (1)
Student Expert
5th Jul, 2019
The official authority institute will publish the JEE Advanced 2019 cutoff for IIT Delhi after the announcement of the result.
As of previous year's cutoff of Indian Institute of Technology, Delhi, for OBC-NCL candidate, the opening rank for computer science and engineering was 38 and closing rank was 65.
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