what is minimum percentile to get a NiT hamirpur in sc category.... chemical engineering
Dear Aspirant
The selection in any NIT on the basis of your rank
And to get admission in it with stream as you mentioned above you need your rank approx.
On home state qouta
Open rank =10778
Closing rank =12303
And
For other state qouta
Open rank =4523
Closing rank =6633
I hope it will help you
Thank you
Reply
Hi
Your profile suggests that your home state is Rajasthan so you will be eligible for other state quota in NIT Hamirpur
This is a bit difficult to predict the percentile required in JEE mains to get a seat as cut off keeps changing every year depending upon various factors like number of students that appeared in the exam, kind of marks obtained by them , toughness level of the jee main examination , number of seats available for the branch you want etc.
But yes,
When we go through previous year trend then ,
In round 6 of josaa counselling 2020 , 6633 sc rank was the closing rank for gender neutral for sc category for other state in NIT Hamirpur for chemical engineering
You can check the same at
https://josaa.nic.in/Result/Result/currentorcr.aspx
And to get around 6633 sc rank, you need at least around 88 percentile as per our rank predictor at
To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to, your home state, your gender etc, the link for jee main college predictor is provided below
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
If you have any other doubt then you can always reach us to clear them :) we are always available to help you out and guide you
Thankyou
