what is rank cut off of obc student by jee mains .in bihar engineering government colleges.
Hey there
Cutoff for OBC NCL in jee mains 2020 is 72.8887969. this is the cutoff which should be a minimum percentile acheived by a candidate for JEE advanced exam.
check the link
https://engineering.careers360.com/articles/jee-main-cutoff
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
good luck
Hello student,
Congratulations on your result.According to NTA, the cutoff for OBC-NCl category is 72.8887969. Since the JEE mains result has been announced, please check your percentile.If your percentile is greater than 72.8887969 , you are eligible to write JEE Advanced
I sugggest you to go through the previous years cut off ranks through the given link
https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits
Feel free to reach out to Careers360 in case you have doubts regarding your career
Related Questions
Know More about
Joint Entrance Examination (Main)
Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Answer Key | Result | Accepting Colleges
Get Updates Brochure
Your Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.
