what is rank cut off of obc student by jee mains .in bihar engineering government colleges.
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Hey there
Cutoff for OBC NCL in jee mains 2020 is 72.8887969. this is the cutoff which should be a minimum percentile acheived by a candidate for JEE advanced exam.
check the link
https://engineering.careers360.com/articles/jee-main-cutoff
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
good luck
Hello student,
Congratulations on your result.According to NTA, the cutoff for OBC-NCl category is 72.8887969. Since the JEE mains result has been announced, please check your percentile.If your percentile is greater than 72.8887969 , you are eligible to write JEE Advanced
I sugggest you to go through the previous years cut off ranks through the given link
https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits
Feel free to reach out to Careers360 in case you have doubts regarding your career
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