what is the area of a rhombus having all sides equal to 8cm each and one pair of angles equal to 60° ?
Hello
The answer to your question is 32√3cm2
U have to use the following axioms in this problem
The diagonals of a rhombus bisect each others at right angles
Sides corresponding to equal angles of a triamgle are equal(isosceles triangle)
U also have to use Pythagoras theorem
Lets have the rhombus drawan with the equal angles vertically opposite to each other and the diagonals drawn
The length of the horizontal diagonal is equal to the length of the top left side of the rhombus which is equal to 8cm(this is because the angles corresponding to these sides are equal to each other)
The lenght of the half of the vertical diagonal is calculated by applying Pythagoras theorem to the top left side of the rhombus which is equal to 4√3cm
Now area of rhombus equals 1/2*diagonal1*diagonal 2
Hope this helped
