Question : What is the area of the lateral surface of a right circular cylinder, If the circumference of the base is 22 cm and its height is four times its radius?
Option 1: 388 cm2
Option 2: 308 cm2
Option 3: 408 cm2
Option 4: 288 cm2
Correct Answer: 308 cm 2
Solution :
Given: The circumference of the base of the cylinder is 22 cm and its height is four times its radius.
Let the radius be $r$.
So, $2\pi r=22$
⇒ $r=22×\frac{7}{22}×\frac{1}{2}$
⇒ $r=\frac{7}{2}$ cm
So, the height = 4 × $\frac{7}{2}$ = 14 cm
Now, the area of the lateral surface of the right circular cylinder
= circumference of the base × height
= 22 × 14
= 308 cm
2
Hence, the correct answer is 308 cm
2
.
Related Questions
Know More about
Staff Selection Commission Multi Tasking ...
Answer Key | Cutoff | Selection Process | Preparation Tips | Eligibility | Application | Exam Pattern
Get Updates Brochure
Your Staff Selection Commission Multi Tasking Staff Exam brochure has been successfully mailed to your registered email id “”.
Upcoming Exams
Trending Articles around SSC MTS
