Question : What is the area of the lateral surface of a right circular cylinder, If the circumference of the base is 22 cm and its height is four times its radius?
Option 1: 388 cm2
Option 2: 308 cm2
Option 3: 408 cm2
Option 4: 288 cm2
Correct Answer: 308 cm 2
Solution :
Given: The circumference of the base of the cylinder is 22 cm and its height is four times its radius.
Let the radius be $r$.
So, $2\pi r=22$
⇒ $r=22×\frac{7}{22}×\frac{1}{2}$
⇒ $r=\frac{7}{2}$ cm
So, the height = 4 × $\frac{7}{2}$ = 14 cm
Now, the area of the lateral surface of the right circular cylinder
= circumference of the base × height
= 22 × 14
= 308 cm
2
Hence, the correct answer is 308 cm
2
.
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