Question : What is the area of the lateral surface of a right circular cylinder, If the circumference of the base is 22 cm and its height is four times its radius?
Option 1: 388 cm2
Option 2: 308 cm2
Option 3: 408 cm2
Option 4: 288 cm2
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Correct Answer: 308 cm 2
Solution : Given: The circumference of the base of the cylinder is 22 cm and its height is four times its radius. Let the radius be $r$. So, $2\pi r=22$ ⇒ $r=22×\frac{7}{22}×\frac{1}{2}$ ⇒ $r=\frac{7}{2}$ cm So, the height = 4 × $\frac{7}{2}$ = 14 cm Now, the area of the lateral surface of the right circular cylinder = circumference of the base × height = 22 × 14 = 308 cm 2 Hence, the correct answer is 308 cm 2 .
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