790 Views

What is the degreeof(x-a)(x-b)(x-c)(x-d)(x-e)(x-f).........(x-z)after simplification?


Farhath 29th Jan, 2018
Answers (2)
Rakesh Sai 6th Dec, 2019
Hi
If you consider the expression (x-a)(x-b)(x-c).....(x-x)(x-y)(x-z)
Then clearly from the above expression (x-x ) would be zero so the product would be zero.
So degree zero
If you consider X  as a variable and a,b,c...z as constants then the degree would be  26
vanam anusha 3rd Jul, 2018

hello,

You go through the below link

View Answer - Student Community ...


Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
UPES MBA Admissions 2025
Apply
Ranked #41 amongst institutions in Management by NIRF | 100% Placement | Last Date to Apply: 28th April
UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements | Last Date to Apply: 28th April
UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS University Rankings | 16.6 LPA Highest CTC | L...
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
UPES | BBA Admissions 2025
Apply
#41 in NIRF, NAAC ‘A’ Grade | 100% Placement, up to 30% meritorious scholarships | Last Date to Apply: 28th April
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books