Correct Answer: $3x-2y=-6$

Solution : The equation of the given line is $2x+3y=–6$
The y-intercept is $3$.
According to the question,
A line with slope $m$ is represented as $y=mx+c$
Given line, $2x+3y=–6$
⇒ $y=-\frac{2}{3}x-2$
Slope of the line $=–\frac{2}{3}$
The product of the slope of two perpendicular lines is $–1$.
So, the slope of the required line is $=(–\frac{1}{–\frac{2}{3}}) = \frac{3}{2}$
The equation of the line is
$y=\frac{3}{2}x+c$
Given y-intercept ($c$) $=3$,
Now, $ y=\frac{3}{2}x + 3$
⇒ $2y=3x+6$
Therefore, the equation of the required line is $3x-2y=-6$
Hence, the correct answer is $3x-2y=-6$.