What is the frequency and wavelength photon emmited during a transition from n=5 n=2 from an hydrogen atom
Answer (1)
9th Aug, 2020
Using Rydberg’s formula, we have: v = R*[1/(n1^2) – 1/(n2^2)]
where v = frequency in cm^-1
R = Rydberg’s Constant = 109677.6 in cm^-1
n1 = 2 (Given)
n2 = 5 (Given)
Substituting the values, we get:
v = 109677.6 * [1/(2^2) – 1/(5^2)]
V = 109677.6 * [1/4-1/25]
v = 23,032.296 cm^-1 (Answer)
We know, wavelength = 1/frequency = 1/23032.296
Wavelength = 4.34 * 10^-5 cm (Answer)
Comments (0)
Related Questions
Trending Articles/News
How to Prepare for CAT 2024 in 4 months?
6 minutes ago
How to Prepare for CAT 2024 Exam in 3 Months?
13 minutes ago
How to Prepare for CAT 2024 in 2 Months?
18 minutes ago
