Question : What is the Highest Common Factor of $\frac{4}{55}$, $\frac{2}{11}$, and $\frac{8}{22}$?
Option 1: $\frac{1}{66}$
Option 2: $\frac{3}{88}$
Option 3: $\frac{2}{55}$
Option 4: $\frac{1}{55}$
Correct Answer: $\frac{1}{55}$
Solution :
Given: The numbers are $\frac{4}{55}$, $\frac{2}{11}$, and $\frac{8}{22}$
Highest Common Factor (HCF) of fraction = $\frac{\text{HCF of numerator}}{\text{LCM of denominator}}$ where LCM is the Least Common Multiple.
HCF of (4, 2, 8) = 2
LCM of (55, 11, 22) = $11\times 2\times 5 = 110$
Highest Common Factor (HCF) of fractions $\frac{4}{55}$, $\frac{2}{11}$, and $\frac{8}{22}=\frac{2}{110}=\frac{1}{55}$
Hence, the correct answer is $\frac{1}{55}$.
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