Question : What is the length of the longest rod that can be placed in a room of dimensions 12 m × 9 m × 8 m?
Option 1: 15 m
Option 2: 17 m
Option 3: 16 m
Option 4: 14 m
Correct Answer: 17 m
Solution : Given: Dimension of the room = 12 m × 9 m × 8 m Length of the longest rod= $\sqrt{l^2+b^2+h^2}$ [where $l,b,h$ are length, breadth, and height respectively.] = $\sqrt{12^2+9^2+8^2}$ = $\sqrt{144+81+64}$ = $\sqrt{289}=17$ Hence, the correct answer is 17 m.
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Question : The longest rod that can be placed in a room is 12 metres long, 9 metres broad, and 8 metres high is:
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Question : The value of $\frac{2}{3} \div \frac{3}{10}$ of $\frac{4}{9}-\frac{4}{5} \times 1 \frac{1}{9} \div \frac{8}{15}-\frac{3}{4}+\frac{3}{4} \div \frac{1}{2}$ is:
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