what is the minimum percentile for OBC candidate to get NIT seat all over india
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Hi
It is not easy to predict the marks/percentile/rank required in JEE mains as closing rank keeps changing every year depending upon various factors like number of students that appeared in the exam, kind of marks obtained by them , toughness level of the jee main examination , number of seats available for the branch you want etc.
But yes,
When we go through previous year trend then ,
Under other state quota , closing rank for some of the nits for which closing rank goes low are listed below along with their closing rank in the 6th round of josaa counselling 2020 for obc category :-
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NIT Sikkim ,civil engineering :- 13352 obc rank
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NIT Mizoram ,civil engineering :-14730 obc rank
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Nit Ap, Metallurgical and Materials Engineering (4 Years, Bachelor of Technology) :- 14902 obc rank
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Nit nagaland ,Electronics and Instrumentation Engineering (4 Years, Bachelor of Technology) :- 15340 obc rank
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National Institute of Technology AgartalaProduction Engineering (4 Years, Bachelor of Technology :- 15659 obc rank
You can verify the above at
https://josaa.nic.in/Result/Result/currentorcr.aspx
So, to get a seat in NIT you should get at least around 15000 OBC rank i. e around 95 percentile .
This prediction of is on the basis of past year data but cut off/closing rank for colleges keeps changing every year depending upon many factors like number of students that appeared in the examination, difficulty level of the JEE main question paper for different shifts etc
To get a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to, your home state, your gender etc, the link for jee main college predictor is provided below
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
To prepare well for jee main, visit
https://learn.careers360.com/knockout-jee-main
Thankyou
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