what is the minimum percentile is needed to get cse branch in lnmiit Jaipur raj.
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Answer (1)
4th Nov, 2020
Hello aspirant!!
Hope you are doing well. The minimum percentile you need to have is 80% to get admission in CSE branch in LNMIT Jaipur. If you have more than this percentile you can have more chances of getting admission. Cut off marks for LNMIT are as follows
1.BTECH CSE - 135-145
2.CCE-122-133
3. ECE- 108-118
4. ME-96-106
Dual degree BTECH +MTECH
1.CSE-120-130
2. ECE - 96-106
These are the cut off marks in 2020 in LNMIT Jaipur college. Hope you got some clear idea on this.
All the best!!
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