51 Views

what is the minimum percentile is needed to get cse branch in lnmiit Jaipur raj.


Recommended : Get important details about LNMIIT Jaipur. Download Brochure
sanatkumar295 25th Sep, 2020
Answer (1)
URE SHRUTI 4th Nov, 2020

Hello aspirant!!

Hope you are doing well. The minimum percentile you need to have is 80% to get admission in CSE branch in LNMIT Jaipur. If you have more than this percentile you can have more chances of getting admission. Cut off marks for LNMIT are as follows

1.BTECH CSE - 135-145

2.CCE-122-133

3. ECE- 108-118

4. ME-96-106

Dual degree BTECH +MTECH

1.CSE-120-130

2. ECE - 96-106

These are the cut off marks in 2020 in LNMIT Jaipur college. Hope you got some clear idea on this.

All the best!!

Compare Colleges

College Comparison based on Courses, Placement, Rank, Fee

Compare Now

Know More About

Related Questions

UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest CTC 50 LPA , 100% Placements
UEM Jaipur MCA Admissions 2025
Apply
Scholarships to meritorious students | UGC recognized university
Chanakya University BCA Admis...
Apply
Scholarships Available | Approved by UGC
Chanakya University B.sc Admi...
Apply
Scholarships Available | Top notch Faculty
Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities In QS Asia Rankings 2025 | Scholarships worth 210 CR
Symbiosis-SITEEE-2025
Apply
Gateway for admissions to Engineering courses @ Symbiosis
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books