what is the minimum percentile required from the jee mains to get admission in ipu 1st year btech admission for general catagory

Hello sonali,

For getting admission in ipu through JEE main you need to score

1. 50-60 + marks ( for delhi residence)

2. 100+ marks if you are from other state.

It is just because delhi people get 85% relaxation in admission.

Their is another way also to get addmission in ipu other than JEE main.

Ipu also condut its own exam every year but it also have 85% seats for local residence( people of delhi)

Hope this information helps you

Good luck

Hello,

To get admission through IPUCET based on JEE Main merit you need to score the minimum cut off marks specified by NTA. JEE Main 2020 cut off is not yet declared it will be out after the results are declared. In 2019 NTA JEE Main cut off mark for general category was 89.7548849 percentile considering this you need to score 90 or above percentile as cut off may increase or decrease depending on number of candidates appeared, difficulty of exam etc. Now, to get seat through IPU CET you need to score the cut off specified by the participating institutes and the cut off is different for each college. You need to score in between 90-95 percentile to have decent chances of getting seat.

You may try our JEE Main knockout package to help you with your preparation

https://learn.careers360.com/knockout-jee-main-april/

You can check the college specific cut off in here https://engineering.careers360.com/articles/ipu-btech-cutoff

There is no any fixed percentile, it depands on the number of seats, the score of other students and course which you wants to adopt. But you can get idea by seeing last year's cutoff list. I am attaching a link where you can find last year cutoff

https://www.google.com/amp/s/engineering.careers360.com/articles/ipu-btech-cutoff/amp