Question : What is the percentage composition of the element of H2SO3?
Option 1: 2.5% of H, 58.5% of S, 39% of O
Option 2: 33% of H, 16% of S, 51% of O
Option 3: 58.5% of H, 39% of S, 2.5% of O
Option 4: 2.5% of H, 39% of S, 58.5% of O
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Correct Answer: 2.5% of H, 39% of S, 58.5% of O
Solution : The correct option is 2.5% H, 39% S, 58.5% O .
Molar mass of H 2 SO 3 = (2 x 1 g/mol) + (1 x 32 g/mol) + (3 x 16 g/mol) = 82 g/mol.
- Hydrogen (H): (2*molar mass of H)/(molar mass of H 2 SO 3 )*100% = (2 g/mol/82 g/mol)*100% ≈ 2.44%;
- Sulphur (S): (1*molar mass of S)/(molar mass of H 2 SO 3 )*100% = (32 g/mol/82 g/mol)*100% ≈ 39.02%;
- Oxygen (O): (3*molar mass of O)/(molar mass of H 2 SO 3 )*100% = (3*16 g/mol/82 g/mol)*100% ≈ 58.54%.
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