What is the percentile for 220 /390 jee mains paper 2

Hello anushka,

So, the total number of candidates who appeared for JEE Main 2019 January exam was around 8.74 lakhs. The exam was conducted on four days in two slots (4 days x 2 slots = 8 sessions in total). So, approximately 1.09 lakh students took the exam in each session. Note that the JEE Main 2019 results/scorecard mentions only the NTA score for each subject and not the subject-wise marks secured by candidates. The percentile score displayed against each of the subjects and the overall percentile score is calculated up to 7 decimals using a pre-determined formula.







So, to convert your JEE Main Percentile into a Rank, you need the following figures:



Your NTA scoreTotal number of students who have appeared for the examPercentage of students below or equal to your marksPercentage of students above your marksNumber of students above your marks







While the data for the first two aspects is easily available, the figures for the other three data points are difficult to find. To calculate these, here's what you need to do.



Lets assume:



Your NTA score =



P



Total Number of Students =



N



Percentage of students below or equal to your marks =



P







Example: if you have secured a 70 percentile in JEE Main, which means that 70% of the candidates who appeared for JEE Main are below or at the same level as you are



Percentage of students above your marks =



100 - P



Number of students above your marks



((100  P)/100)*N



Now, the formula to calculate JEE Main 2019 Rank from Percentile Score is:



((100 -P)/100)*N + 1

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