What is the qualifying mark for OBC in JEE ADVANCED??
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Hello Aspirant,
Hope you are doing well.
Indian Institute of Technology(IIT) Delhi has released JEE Advanced qualifying marks for each category. According to the JEE Advanced cutoff 2020 for OBE -NLC candidates Minimum percentage of marks in each subject is 9% and Minimum percentage of Aggregate Marks is 31.5%. Their will be different cutoff's for different institutes. If you want to know cutoff's of each colleges you can go through this link: https://engineering.careers360.com/articles/jee-advanced-cutoff
If you want to predict your college you can go through this link: https://engineering.careers360.com/jee-advanced-college-predictor?icn=QnA&ici=qna_answer
Hope this helps you.
All the Best!!!
Dear Aspirant, JEE Advanced 2020 was conducted by IIT Delhi on 27th of September. Those candidates who score minimum percentage of marks in each subject as well as score minimum percentage of aggregate marks will be eligible to get into IIT.
Minimum percentage of marks required in each subject for OBC-NCL candidates is 9%
Minimum percentage of aggregate marks required for OBC-NCL is 31.5%
For more details check out this link:
https://engineering.careers360.com/articles/jee-advanced-cutoff/amp#referrer=https://www.google.com
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