Question : What is the radius of the circle that circumscribes the triangle ABC whose sides are 16, 30, and 34 units respectively?
Option 1: 16 Units
Option 2: 17 Units
Option 3: 28 Units
Option 4: 34 Units
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Correct Answer: 17 Units
Solution :
Dimension of triangle = 16, 30, 34 units
In triangle ABC,
$\because$ 34
2
= 16
2
+ 30
2
This means it is a Pythagorean triplet and the triangle ABC is a right-angle triangle.
$\therefore$ Radius of circle which circumscribes the triangle ABC= $\frac{\text{Hypotenuse}}{2}$ = $\frac{34}{2}$ = 17 units.
Hence, the correct answer is 17 Units.
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