What is the rank required to pass jee main exam
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Hi Alfiya,
On analysing the cutoff marks for jee mains 2019 the results are as follows for different categories :-
Category
Total NTA Score Cutoff Based on Paper 1
Common Rank List (CRL)
89.7548849
GEN-EWS
78.2174869
Other Backward Classes (OBC-NCL)
74.3166557
Scheduled Caste (SC)
54.0128155
Scheduled Tribe (ST)
44.3345172
PwD
0.11371730
Hello aspirant . Kindly mention the name of your category. Assuming that you are from General Category , rank around 223000 to 224000 is eligible for JEE Advance. In order to get NIT , for Top NITs you need to have a score of 220 to 200 . For lower NITs 150 to 180. In Some NITs you would get core branch , with a score of 120 as well
All the best..
JEE Main 2019 Qualifying Cutoff
Category
Total NTA Score Cutoff Based on Paper 1
Common Rank List (CRL)
89.7548849
GEN-EWS
78.2174869
Other Backward Classes (OBC-NCL)
74.3166557
Scheduled Caste (SC)
54.0128155
Scheduled Tribe (ST)
44.3345172
PwD
0.11371730
https://engineering.careers360.com/articles/jee-main-cutoff
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