Question : What is the ratio of inradius and circumradius of an equilateral triangle?
Option 1: 1 : 2
Option 2: 1 : 3
Option 3: 1 : 4
Option 4: 3 : 2
Correct Answer: 1 : 2
Solution : Let $a$ be the side of the equilateral triangle. Circumradius = $\frac{abc}{4 \times \text{Area of triangle}}$, where $a,b,c$ are sides In Case of equilateral triangle, abc = a 3 and area of triangle = $\frac{\sqrt{3}a^{2}}{4}$ $\therefore$ Circumradius = $\frac{a^{3}}{4 \times \frac{\sqrt3a^{2}}{4}}=\frac{a}{\sqrt{3}}$ Inradius = $\frac{\text{Area of triangle}}{\text{Semi perimeter of triangle}}$ Semi-perimeter = half of the sum of all sides $\therefore$ Inradius = $\frac{\frac{\sqrt{3}a^{2}}{4}}{\frac{3a}{2}} = \frac{a}{2\sqrt{3}}$ Therefore, Inradius : Circumradius = $\frac{a}{2\sqrt{3}}$: $\frac{a}{\sqrt{3}}$= 1 : 2 Hence, the correct answer is 1 : 2.
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Question : The ratio of inradius and circumradius of an equilateral triangle is:
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