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What is the required cutoff in MET for b.tech (cse) at Manipal jaipur 2019?


Tanishq 12th Mar, 2019
Answer (1)
Punya Asthana 21st Apr, 2019

Hello Aspirant,

According to previous year data, the closing rank for Manipal Jaipur was 10867 rank. So, the approximate marks may be ranging from 100 to 120.

Manipal Academy of Higher Education (formerly Manipal University) will conduct the MET 2019 from April 19 to 28 across various test centres.

Candidates were provided with the slot booking facility from April 5 till April 9. The last date to fill MET 2019 application form was April 8. The exam conducting authorities will conduct MET 2019 in complete online mode from April 19 to 28. MET 2019 (1st and 2 nd attempt) will be held in 85 Indian cities and Dubai.

Only two attempts will be conducted from this year. Admissions to Manipal Institute of Technology, Manipal; Sikkim Manipal Institute of Technology, Sikkim and Manipal University, Jaipur will be through MET 2019. Candidates who have secured at least 50% marks in their Class 12 th can apply for M ET .

The result of MET 2019 will be announced probably in the first week of May.


The minimum rank required to get admission is the cutoff of MET 2019. Candidates who will not meet MU OET 2019 cutoff will have fewer chances of admission in comparison to those who have ranks more than or equivalent to cutoff.

The authorities of Manipal will prepare and release MET cutoff 2019 considering certain influential factors. However, it is to be noted that the cutoff of MET 2019 will be released with opening and closing ranks and for different categories, institutes and B.Tech programmes as offered through MET entrance exam.

All the best!

1 Comment
Comments (1)
22nd Apr, 2019
Thank you....
Reply
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