Question : What is the smallest three-digit number which, when divided by 8 or 6, leaves a remainder of 1 in each case?
Option 1: 121
Option 2: 119
Option 3: 123
Option 4: 125
New: SSC MTS 2024 Application Form OUT; Direct Link
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 121
Solution : Given, The smallest 3-digit number leaves 1 remainder when divided by 8 or 6. 8 = 2 × 2 × 2 6 = 3 × 2 ⇒ LCM of 8 and 6 = 2 × 2 × 2 × 3 = 24 When we divide 100 by 24, we get 4 as the remainder The smallest three-digit number which is divisible by 8 or 6 = 100 – 4 + 24 = 120 The smallest three-digit number, when divided by 8 or 6 leaves the remainder 1 in each case = (120 + 1) = 121. Hence, the correct answer is 121.
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Question : What is the smallest three-digit number when divided by 2, 3, and 4 leaving the remainder 1 in each case?
Question : A number, when divided by 80, leaves a remainder of 20. What is the remainder when the same number is divided by 16?
Question : What is the greatest four-digit number which when divided by 3 and 4 leaves remainder 2 in each case?
Question : Find the second smallest number which, when divided by 81 or 63, leaves a remainder of 7 in each case.
Question : When N is divided by 6, the remainder is 4. When 2N is divided by 6, the remainder is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile