Question : What is the solution of the following equations? 2x + 3y = 12 and 3x – 2y = 5
Option 1: x = 3, y = 2
Option 2: x = 2, y = 3
Option 3: x = –2, y = 3
Option 4: x = 3, y = –2
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: x = 3, y = 2
Solution : Given: The equations are 2x + 3y = 12 and 3x – 2y = 5. Find the values of the variables x and y by solving the simultaneous linear equations. 2x + 3y = 12 (equation 1) 3x – 2y = 5 (equation 2) Multiply equation (1) with 2 and equation (2) with 3 and add them, 2(2x + 3y) + 3(3x – 2y) = 2 × 12 + 3 × 5 ⇒ 4x + 6y + 9x – 6y = 24 + 15 ⇒ 13x = 39 ⇒ x = 3 Substitute the value of x in the equation (1), 2 × 3 + 3y = 12 ⇒ 6 + 3y = 12 ⇒ 3y = 12 – 6 ⇒ 3y = 6 ⇒ y = 2 Hence, the correct answer is x = 3, y = 2.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : What is the equation of the line perpendicular to the line $2x+3y=-6$ and having y-intercept 3?
Question : The graphs of the equations $4 x+\frac{1}{3} y=\frac{8}{3}$ and $\frac{1}{2} x+\frac{3}{4} y+\frac{5}{2}=0$ intersect at a point P. The point P also lies on the graph of the equation:
Question : If $( x^{3}-y^{3}):( x^{2}+xy+y^{2})=5:1$ and $( x^{2}-y^{2}):(x-y)=7:1$, then the ratio $2x:3y$ equals:
Question : If $2x-4\leq \frac{2-x}{3}$ and $2(2x+5)>3x-5$, then $x$ can take which of the following values?
Question : The simplified form of $(x+2y)^3 + (x-2y)^3$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile