Question : What is the sum of all two-digit even numbers?
Option 1: 2430
Option 2: 2410
Option 3: 2470
Option 4: 2520
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Correct Answer: 2430
Solution : The first 2 digit number is 10 and the last two-digit number is 98. Sum = $\frac{n}{2}(\text{first term + last term})$ Number of terms = $\frac{(98 - 10)}{2} + 1$ = 45 Now, we can find the sum: Sum = $\frac{45}{2}(10 + 98)$ ⇒ Sum = $45\times54$ ⇒ Sum = 2430 Therefore, the sum of all two-digit even numbers is 2430. Hence, the correct answer is 2430.
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