Question : What is the value of $\frac{44–13+17–21+45–24}{12 \text { of } 4–3 \times 4–6 \times 2}$?
Option 1: 1
Option 2: 2
Option 3: –2
Option 4: –1
Answer (1)
18th Jan, 2024
Correct Answer: 2
Solution :
$\frac{44–13+17–21+45–24}{12 \text { of } 4–3 \times 4–6 \times 2}$
=$\frac{106–58}{48–3 \times 4–6 \times 2}$
= $\frac{48}{48–12–12}$
=$\frac{48}{48–24}$
=$\frac{48}{24}=2$
Hence, the correct answer is 2.
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