Question : What is the value of $\frac{44–13+17–21+45–24}{12 \text { of } 4–3 \times 4–6 \times 2}$?
Option 1: 1
Option 2: 2
Option 3: –2
Option 4: –1
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Correct Answer: 2
Solution : $\frac{44–13+17–21+45–24}{12 \text { of } 4–3 \times 4–6 \times 2}$ =$\frac{106–58}{48–3 \times 4–6 \times 2}$ = $\frac{48}{48–12–12}$ =$\frac{48}{48–24}$ =$\frac{48}{24}=2$ Hence, the correct answer is 2.
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