Question : What is the value of $\frac{7}{11} \div \frac{21}{33} \times \frac{5}{12}+\frac{10}{36} \times \frac{6}{11} \div \frac{18}{33}$?
Option 1: $\frac{29}{35}$
Option 2: $\frac{25}{36}$
Option 3: $\frac{28}{39}$
Option 4: $\frac{24}{41}$
Correct Answer: $\frac{25}{36}$
Solution :
$\frac{7}{11} \div \frac{21}{33} \times \frac{5}{12}+\frac{10}{36} \times \frac{6}{11} \div \frac{18}{33}$
$=\frac{7}{11} \times \frac{33}{21} \times \frac{5}{12}+\frac{10}{36} \times \frac{6}{11} \times \frac{33}{18}$
$= \frac{5}{12}+\frac{5}{18}$
$= \frac{15+10}{36}$
$=\frac{25}{36}$
Hence, the correct answer is $\frac{25}{36}$.
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