Question : What is the value of $\frac{7}{11} \div \frac{21}{33} \times \frac{5}{12}+\frac{10}{36} \times \frac{6}{11} \div \frac{18}{33}$?
Option 1: $\frac{29}{35}$
Option 2: $\frac{25}{36}$
Option 3: $\frac{28}{39}$
Option 4: $\frac{24}{41}$
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Correct Answer: $\frac{25}{36}$
Solution : $\frac{7}{11} \div \frac{21}{33} \times \frac{5}{12}+\frac{10}{36} \times \frac{6}{11} \div \frac{18}{33}$ $=\frac{7}{11} \times \frac{33}{21} \times \frac{5}{12}+\frac{10}{36} \times \frac{6}{11} \times \frac{33}{18}$ $= \frac{5}{12}+\frac{5}{18}$ $= \frac{15+10}{36}$ $=\frac{25}{36}$ Hence, the correct answer is $\frac{25}{36}$.
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