Question : What is the value of $\sin 30^{\circ}+\cos 30^{\circ}+\tan 30^{\circ}$?
Option 1: $\frac{5+\sqrt{3}}{2 \sqrt{3}}$
Option 2: $\frac{5-\sqrt{3}}{2 \sqrt{3}}$
Option 3: $\frac{5+\sqrt{3}}{\sqrt{3}}$
Option 4: $\frac{5-\sqrt{3}}{\sqrt{3}}$
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $\frac{5+\sqrt{3}}{2 \sqrt{3}}$
Solution : Given: $\sin 30^{\circ}+\cos 30^{\circ}+\tan 30^{\circ}$ Putting the values, we get: $=\frac{1}{2}+\frac{\sqrt3}{2}+\frac{1}{\sqrt3}$ $=\frac{\sqrt3+3+2}{2\sqrt3}$ $=\frac{5+\sqrt3}{2\sqrt3}$ Hence, the correct answer is $\frac{5+\sqrt3}{2\sqrt3}$.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : What will be the value of $\frac{\sin 30^{\circ} \sin 40^{\circ} \sin 50^{\circ} \sin 60^{\circ}}{\cos 30^{\circ} \cos 40^{\circ} \cos 50^{\circ} \cos 60^{\circ}}$?
Question : The value of $\frac{4 \tan ^2 30^{\circ}+\sin ^2 30^{\circ} \cos ^2 45^{\circ}+\sec ^2 48^{\circ}-\cot ^2 42^{\circ}}{\cos 37^{\circ} \sin 53^{\circ}+\sin 37^{\circ} \cos 53^{\circ}+\tan 18^{\circ} \tan 72^{\circ}}$ is:
Question : What is the value of $5 \sqrt{3} \cos 60^{\circ} \tan 30^{\circ}-3 \cos 0^{\circ}+3 \cos ^2 45^{\circ}+2 \sin ^2 60^{\circ}$?
Question : Find the value of $\frac{\cos^2 15^{\circ}-\sin^2 15^{\circ}}{\cos^2 145^{\circ}+\sin^2 145^{\circ}}$.
Question : Using $\cos (A+B)=\cos A \cos B-\sin A \sin B$, find the value of $\cos 75^\circ$.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile