Question : What is the value of (3x3 + 5x2y + 12xy2 + 7y3), when x = – 4 and y = – 1?
Option 1: – 329
Option 2: – 359
Option 3: – 361
Option 4: – 327
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Correct Answer: – 327
Solution :
Put x = – 4 and y = – 1
3x
3
+ 5x
2
y + 12xy
2
+ 7y
3
= 3(– 4)
3
+ 5(– 4)
2
(–1) + 12(–4)(–1)
2
+ 7(–1)
3
= – 192 – 80 – 48 – 7
= – 327
Hence, the correct answer is – 327.
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