Question : What is the value of (3x3 + 5x2y + 12xy2 + 7y3), when x = – 4 and y = – 1?
Option 1: – 329
Option 2: – 359
Option 3: – 361
Option 4: – 327
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Correct Answer: – 327
Solution : Put x = – 4 and y = – 1 3x 3 + 5x 2 y + 12xy 2 + 7y 3 = 3(– 4) 3 + 5(– 4) 2 (–1) + 12(–4)(–1) 2 + 7(–1) 3 = – 192 – 80 – 48 – 7 = – 327 Hence, the correct answer is – 327.
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