Question : What is the value of $3 \tan 20° \tan 45°\tan 70°$?
Option 1: 2
Option 2: 3
Option 3: 1.5
Option 4: 4
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 3
Solution : $3 \tan 20°\tan 45° \tan70°$ $= 3 \tan 20°\tan 45° \tan (90° - 20°)$ [Using $\tan \theta = \cot (90° - \theta)$] $= 3 \tan 20°\tan 45°\cot 20°$ $= 3 \times \tan 45°$ $= 3 \times 1$ $= 3$ Hence, the correct answer is 3.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : What is the value of $\tan 10°. \tan 25°. \tan 45°.\tan 65°. \tan 80°$
Question : If $2\tan^2A+4\cos^4A=3$, then the possible value of $A$ is:
Question : The value of $\frac{\sec 54^{\circ}}{\operatorname{cosec} 36^{\circ}}+\frac{\tan 70^{\circ}}{\cot 20^{\circ}}-2 \tan 45^{\circ}$ is equal to:
Question : What is the value of $\left(\tan 10^{\circ} \tan 80^{\circ}+\tan 20^{\circ} \tan 70^{\circ}+\tan 30^{\circ} \tan 60^{\circ}+\tan 40^{\circ} \tan 50^{\circ}\right)$?
Question : If $\cos 20°= m$ and $\cos 70°=n$, then the value of $m^2+n^2$:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile