Question : What is the value of $3^{2}+7^{2}+11^{2}+13^{2}+17^{2}-1^{2}-5^{2}-9^{2}-11^{2}-15^{2}?$
Option 1: 5
Option 2: 72
Option 3: 92
Option 4: 184
Correct Answer: 184
Solution : $3^{2}+7^{2}+11^{2}+13^{2}+17^{2}-1^{2}-5^{2}-9^{2}-11^{2}-15^{2}$ $= 9+49+121+169+289-1-25-81-121-225$ $=184$ Hence, the correct answer is 184.
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Question : $4^{11}+4^{12}+4^{13}+4^{14}$ is divisible by:
Question : The value of $\left(5 \frac{1}{4} \div \frac{3}{7}\right.$ of $\left.\frac{1}{2}\right) \div\left(5 \frac{1}{9}-7 \frac{7}{8} \div 9 \frac{9}{20}\right) \times \frac{11}{21}+\left(2 \div 2\right.$ of $\left.\frac{1}{2}\right)$ is:
Question : Directions: If 72 A 7 B 9 = 16, and 52 A 5 B 7 = 12, then 92 A 3 B 8 = ?
Question : Arrange the given ratios in descending order 15 : 7, 5 : 11, and 21 : 77.
Question : The value of $\left(5 \div 2\right.$ of $\left.\frac{1}{2}\right)+\left(5 \frac{1}{4} \div \frac{3}{7}\right.$ of $\left.\frac{1}{2}\right) \div\left(5 \frac{1}{9}-7 \frac{7}{8} \div 9 \frac{9}{20}\right) \times \frac{11}{21}$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile