Question : What is the value of $\frac{(55 + 88) [(3 \times 5 + 4)–64\div 8]}{28\times 7\div56\times 4 \text { of }(91–78)}$?
Option 1: $\frac{121}{12}$
Option 2: $\frac{121}{11}$
Option 3: $\frac{121}{13}$
Option 4: $\frac{121}{14}$
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Correct Answer: $\frac{121}{14}$
Solution : $\frac{(55 + 88) [(3 \times 5 + 4)–64\div 8]}{28\times 7\div56\times 4 \text { of }(91–78)}$ $=\frac{143\times [(15 + 4)–64\div 8]}{28\times 7\div56\times 4 \text { of }13}$ $=\frac{143\times [19–64\div 8]}{28\times 7\div56\times 52}$ $=\frac{143\times [19–8]}{28\times \frac{1}{8}\times 52}$ $=\frac{143\times 11}{14\times 13}$ $=\frac{121}{14}$ Hence, the correct answer is $\frac{121}{14}$.
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